Forum Replies Created
We will have the access to the videos also till 22nd March. Right? .Just wanted to confirm.
That’s nice Savita .Actually, Lot of topics to choose from.
Thank you, Ken. I was considering some of these topics for the assignment.
Yes Savita, agreed. we need to practice it, otherwise we tend to forget the things.
I found triple method to find the distance of the point from the line to be very simple, easy to understand and fast. Moreover,
in finding the final answer ,we have to do calculations for the middle element only(for distance).I remember, how much calculations we had to do with conventional method .
challenge question #21
since in a triple, one element is always divisible by 3.That means , if we consider one of the elements, for example ,to be either
3 / 6 /9 / 12 / 15 / 18 / 21 /24/27/30 etc. (multiples of 3).Their corresponding squares will be,
9/36/81/144/324/441/729/900.And their corresponding digit sums will be
9/9/9/9/9/9/9 .And 9 ‘s can be casted out.
so the digit sum of squares of one element(other than the one divisible by 3) will be equal to the digit sum of square of the 3rd element(of course, the remaining element).
we can verify this by applying the digit sum check.
- TRIPLET 3, 4 5———————-digit sum check—————->3 IS DIVIBLE BY 3 ,SO RULED OUT.
- L.H.S= DS(4^2 )=DS(16)=7,R.H.S=DS(5^2)= DS(5^2)=DS(25)=7 ,L.H.S=R.H.S
2.TRIPLET 24, 7 25——————–digit sum check——————->24 IS DIVIBLE BY 3 ,SO RULED OUT.
Yes Ken. So, we can do this by at least 3 ways .Thank you.
one way is to multiply and divide by square root of 25.
square root of 3=square root (3 * 25)/ square root(25).
we need to verify if 77 , 36 and 85 is a triple by checking their digit sums.
77 ^2 + 36 ^2 = 85^2
Their corresponding digit sums will be,
L.H.S= 5 ^2 + 9 ^2
=digit sum(25 + 18)
since their digit sums are same, we can say that 77,36 and 85 is a triplet.
can we do this way?
if we write 847/236 = 847/59 * 1/4
then 59 can be written as 6(1).
taking 6 as divisor and (1) as bar digit, got answer =14.35
and then halving it twice,14.35/2=7.175, 7.175/2=3.5875
Thanks Ken. Got it. By mistake ,I took remainder as 5 instead of -5. Also, gone through the explanation of the solution posted in the forum(week9). Here, since the coefficient of x^2 is 3 ,we have to use treble of 4.Also,Understood the next step .
Thank you .While solving the quadratic equation, 3 x^2 – 5 x -7=0,by Vedic Method,
13| 7 . 0 0 0
5 (2) (11)
3. (4) (3)
I am not getting ,how did we obtain (2) (11),(4) and(3)? Up to 3 remainder 5 is okay. Next step, if we divide 50 by 13 ,we get 3 remainder 11.Please explain.
In lesson 30, Calculus, for getting the solution of a quadratic equation by Vedic method,
3 x^2- 5x- 7 = 0,
can we take a=2 ( first divisor) instead of a=3?
if we put x=2 in the left hand side ,we get value equal to -5 (5 units less than 0)and by taking x=5, we get value equal to 5(5 units
more than o).In any case ,difference of 5. Just a thought.
Okay. Actually I meant multiplying 7868(with base=7000) and 9(with base=10).
okay, understood. Don’t have to multiply the LHS by 7.Can you please explain how to proceed further with base=7000.
6868/(868).somehow not getting the answer.