# Week 8 Video lessons

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• #28850

• #32837

Hi Ken,

In lesson 30, Calculus, for getting the solution of a quadratic equation by Vedic method,

3 x^2- 5x- 7 = 0,

can we take a=2 ( first  divisor) instead of a=3?

if we put x=2 in the left hand side ,we get value equal to -5 (5 units less than 0)and by taking x=5, we get value equal to 5(5 units

more than o).In any case ,difference of 5. Just a thought.

Thanks

• #32838

Thanks Preeti.

Yes, we can take a=2 rather than 3 and get the answer that way too.

We cover this subject more fully in the Advanced Course.

• #32977

Thank you .While solving  the quadratic equation, 3 x^2 – 5 x -7=0,by Vedic Method,

13|      7 .    0     0       0

5   (2)    (11)

<hr />

3. (4)  (3)

I am not getting ,how did we obtain (2) (11),(4) and(3)?  Up to 3 remainder 5 is okay. Next step, if we divide 50 by 13 ,we get 3 remainder 11.Please explain.

• #32978

Hi Preeti,

Actually we start off with 3 remainder -5.

Then -50 divided by 13 = -4 rem 2.

• #32979

Thanks Ken. Got it. By mistake ,I took remainder as 5 instead of -5. Also, gone through the explanation of the solution posted in the forum(week9). Here, since the coefficient of x^2 is 3 ,we have to use treble of  4.Also,Understood the next step .

• #32984

Hi Ken

I have also the doubt which Preeti has asked. I was not able to understand from where the remainder 11 came. But as you explain that we have started from remainder -5 from (7-13) now I have understood. Thanks

• #33056

Hello,

I have a doubt on Reducing (about minute 34 of video lesson 29). What do you mean with Reducing?

I think it’s the same reducinge that I can see in other video lesson. When I divide 2 numbers i.e. 12/2=6 but with reducing I have for example 12/2=5 with remind 2.

It’s correct? Thanks

• #33057

Hello Fabio,

Yes the reducing works as you say. Every time the quotient is reduced by 1 the remainder increases by the divisor.

So 12/2 = 6 rem 0 = 5 rem 2 = 4 rem 4  etc.