[Preeti Pathak]

Hi Ken,

We will have the access to the videos also till 22nd March. Right? .Just wanted to confirm.

Thanks

[Preeti Pathak]

That’s nice Savita .Actually,  Lot of topics to choose from.

[Preeti Pathak]

Thank you, Ken. I was considering some of these topics for the assignment.

[Preeti Pathak]

Yes Savita, agreed. we need to practice it, otherwise we tend to forget the things.

Thanks

[Preeti Pathak]

Hi,

I found triple method to find the distance of the point from the line to be very simple, easy to understand and fast. Moreover,

in finding the final answer ,we have to do calculations for the middle element only(for distance).I remember, how much calculations we had to do with conventional method .

Thanks

[Preeti Pathak]

Hi,

challenge question #21

since in a triple, one  element is always divisible by 3.That means , if we consider one of the elements, for example ,to be either

3 / 6 /9 / 12 / 15 / 18 / 21 /24/27/30  etc. (multiples of 3).Their corresponding squares will be,

9/36/81/144/324/441/729/900.And their corresponding digit sums will be

9/9/9/9/9/9/9 .And 9 ‘s can be casted out.

so the digit sum of squares of one element(other than the one divisible by 3) will be equal to the digit sum of square of the 3rd element(of course, the remaining element).

we can verify this by applying the digit sum check.

For example

1.  TRIPLET  3, 4 5———————-digit sum check—————->3 IS DIVIBLE BY 3 ,SO RULED OUT.
2.                   L.H.S=  DS(4^2 )=DS(16)=7,R.H.S=DS(5^2)= DS(5^2)=DS(25)=7 ,L.H.S=R.H.S

2.TRIPLET 24, 7 25——————–digit sum check——————->24 IS DIVIBLE BY 3 ,SO RULED OUT.

L.H.S=DS(7^2)=DS(49)=4,R.H.S=DS(25^2)DS(625)=4,L.H.S=R.H.S

Thanks

[Preeti Pathak]

Yes Ken. So, we can do this by at least 3 ways .Thank you.

[Preeti Pathak]

Hi ,

one way is to multiply and divide by square root of 25.

square root of 3=square root (3  * 25)/ square root(25).

[Preeti Pathak]

Hi,

challenge question-19

we need to verify if 77 , 36 and 85 is a triple by checking their digit sums.

77 ^2 + 36 ^2 = 85^2

Their corresponding digit sums will be,

L.H.S= 5 ^2 + 9 ^2

=digit sum(25 + 18)

=7+9= 7

R.H.S=4 ^2

=digit sum(16)=1+6=7

L.H.S=R.H.S

since their digit sums are same, we can say that 77,36 and 85 is a triplet.

Thanks

 

[Preeti Pathak]

Hi !!!
can we do this way?
if we write 847/236 = 847/59 * 1/4
then 59 can be written as 6(1).
847/6(1)

taking 6 as divisor and (1) as bar digit, got answer =14.35
and then halving it twice,14.35/2=7.175, 7.175/2=3.5875
847/236=3.588

[Preeti Pathak]

Thanks Ken. Got it. By mistake ,I took remainder as 5 instead of -5. Also, gone through the explanation of the solution posted in the forum(week9). Here, since the coefficient of x^2 is 3 ,we have to use treble of  4.Also,Understood the next step .

 

[Preeti Pathak]

Thank you .While solving  the quadratic equation, 3 x^2 – 5 x -7=0,by Vedic Method,

13|      7 .    0     0       0

5   (2)    (11)

<hr />

3. (4)  (3)

I am not getting ,how did we obtain (2) (11),(4) and(3)?  Up to 3 remainder 5 is okay. Next step, if we divide 50 by 13 ,we get 3 remainder 11.Please explain.

 

 

[Preeti Pathak]

Hi Ken,

In lesson 30, Calculus, for getting the solution of a quadratic equation by Vedic method,

3 x^2- 5x- 7 = 0,

can we take a=2 ( first  divisor) instead of a=3?

if we put x=2 in the left hand side ,we get value equal to -5 (5 units less than 0)and by taking x=5, we get value equal to 5(5 units

more than o).In any case ,difference of 5. Just a thought.

Thanks

 

 

 

 

[Preeti Pathak]

Okay. Actually I meant multiplying 7868(with base=7000) and 9(with base=10).

Thanks

[Preeti Pathak]

okay, understood. Don’t have to multiply the LHS  by  7.Can you please explain how to proceed further   with base=7000.

6868/(868).somehow not getting the answer.

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