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  • in reply to: Challenge Questions #30291
    Preeti Pathak
    Participant

    Hello,

    Answer of challenge question 5

    3 ab * 61=19947

    First of all, see  the digit in the units place of the answer.It is 7.

    Applying “Last by Last”sutra,we get b=7.

    Now,

    3 a*7* 61=19947

    21a*61= 19947

    Applying digit sums,

    digit sum of 19947=3(casting out 9’s)

    Numbers                            Digit sums

    21a                                        3+a

    61 *                                        7 *

    ——–                                ———

    19947                                   3

    In the digit sums column,

    (3+a) * 7 = 3

    21 * 7a =3

    again, applying digit sums,

    3 * 7a=3

    for this to be true, 7a=9,implies a=2

    so the smudged digits are b=7 and a=2

    327 * 61=19947

    Thanks

     

     

     

    in reply to: Challenge Questions #30290
    Preeti Pathak
    Participant

    Hello,

    Anwer to challenge question 6    234*111=???

    unit digit  : 4(same digit)

    digit in ten’s  place : 3+4=7

    digit in hudredth’s place: 2+3+4=9

    digit in Thousanth’s place: 2+3=5

    digit in ten-thousandth’s place : 2

    so answer will be 25973.If there is any carry over,we have to add them .

    we can do it from left to right also.Don”t forget to add the carry overs.

    so in general, if pqr is a 3 digit number.

    So we need to find pqr*111=?

    ans will be:

    p (p+q) (p+q+r) (q+r) r (taking into consideration the carry overs).

    similarly, 854*111 =94794(in this case ,we have carry overs,we need to take those into account).

    Thanks

    in reply to: Challenge Questions #30261
    Preeti Pathak
    Participant

    Few number of ways in which 2019 can be is  represented as follows(in terms of bar numbers):

    202(1)

    21(81)

    3(981)

    Thanks

     

    in reply to: Week 3 Video Lessons #29902
    Preeti Pathak
    Participant

    Hello,

    Bar numbers in lesson 11(week 3) is a useful concept with many advantages.The bar notation which we used ,were to show repeating numbers after the decimal  point like 3.3333……..=3.(3) i.e 3 point bar 3.

    It was used to show the number pattern which goes on forever(infinity).

    I had an impression that Bar notation can only be used if the number is the decimal number.

    But now I understand that apart from being used in decimal numbers only,it has many more advantages.

    Thanks

     

    in reply to: VMTTC -Students Introduction #29895
    Preeti Pathak
    Participant

    Hi everyone,

    My name is Preeti. I like Maths and was searching for Vedic Maths resources.  I came to  know about the course.To start with, I did Introductory course few months back .I liked and enjoyed it very much.Thank you Ken Sir.I wanted to learn more and increase my knowledge in Vedic Maths. I would like to teach Vedic Maths .

    Its my pleasure to be with you all.

    Preeti

Viewing 5 posts - 31 through 35 (of 35 total)
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