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Thanks Anupama.
That’s right! The bar numbers are really useful.
We’ll see more of them as we go on.
Hi Anupama,
I think you got this question from a late chapter on base division. The method is explained there and is not covered on this course. However the method of straight division which we cover in lesson 25 will easily do it.
From the 15 you subtract 3*1 to get 12. You can’t put down 12 because you know the next number will be 9 at most.
So you put down 9, and the other 3 (from that 12) is prefixed to the next digit to give 34.
Now taking 3*9 from 34 gives 7. But this is too big because at the next step you will be taking 21 from 6. So the 7 must be reduced, and you find it needs to go down to a 5 because then you will have 26 – 3*5 which is the remainder 11.
I hope this makes sense – full makes for determination 🙂
The bar numbers method did not come over – trying again:
13) 2 5 4 6
2 (1) 7 rem -15 = 197 rem -15 = 195 rem 11.Hi Anupama,
This is not a good method for division by 13, but you can still do it – either using bar numbers, or by reducing digits.
With bar numbers:
13 ) <span style=”text-decoration: underline;”>2 5 4 6</span>
<span style=”text-decoration: underline;”>2 (1) 7 rem -15</span> = 197 rem -15 = 195 rem 11Just follow through with the method given and you get: 2 (1) 7 rem -15.
Then remembering the the 197 is 197 thirteens you will need to take two of them over to deal with the negative remainder: 26 – 15 = 11.
The other way starts by noting that you can’t take 3 twos from 5, so you put down 1 and put the other 1 to the left of the 5 to make it into 15. And proceed like that.
Hi Savita,
The Teacher’s Manuals (and also the Cosmic Calculator course) were written to provide syllabuses for different age ranges. These are carefully structured to that end. The worksheets given out at the end of this course will also provide useful structures.
Pebble maths is certainly for younger children and offers an excellent introduction to Vedic maths. It fits in perfectly with the material given here.
For young children it is important that they approach maths as games.
Hi Preeti,
Your solution for 31*34 is fine.
The alternative is to double both numbers and find 62*68 using By One More and then halving twice.For 46*54 you can halve both numbers, find 23*27 and double twice.
Yes that is correct Fabio.
It is a special type of equation – in that type of equation, since the two totals are the same, we equate them to zero.
Tirthaji describes several other such types, and this Sutra makes them really easy to solve.
Hi Preeti,
That is all valid. But please note that these can also be solved using the ‘one more than before’ method with Proportionately (which was the expected method).
