[Basa Mallika Gogulamudi]

Hi Ken,

I want to take this opportunity to thank you for making math fun for my son and many more children. I have enjoyed the course thoroughly. You have not only taught me Vedic maths but also being compassionate and  empathetic. Looking forward to do advanced diploma in the near future. Thanks a lot for this wonderful course. Hope to carry the baton forward and make math fun for more children.

Regards.

Mallika

[Basa Mallika Gogulamudi]

Thank you Deepthi.

TM -IL means Teachers Manual – Intermediate Level   by Ken sir

 

[Basa Mallika Gogulamudi]

Do we have to prepare assignment 2 report in any template/ format?

Thanks.

[Basa Mallika Gogulamudi]

Do we have prepare report any template/format for assignment 2

Thanks.

[Basa Mallika Gogulamudi]

Hi,

123 x ??? = 321??

if I pair 1st two numbers

12 3 x ?? ? = 321 ??

if I divide 321 with 12 I get 26 remainder 9

12 3 x 26 ? = 312 and 9 is a carry from crosswise multiplication.

26 x 3 = 78 +12 x 1= 90 so  last digit should be 1 in the multiplier.

123 x 261 = 32103

 

Regards.

[Basa Mallika Gogulamudi]

Hi,

I want to share this with the class.

This is regarding coordinate geometry, perpendicular lines.

We should interchange the coefficients and change one sign to find the equation of the line through a given point and perpendicular to the line. In that case we will have two possible answers (one positive and one negative).

For example: (-3, 4) , 5x -2y =3

Scenario 1 : 2x+5y = 14

Scenario 2 : -2x-5y = -14

Both scenarios plot the same line(same equation) extending over different quadrants.

Regards.

[Basa Mallika Gogulamudi]

Thanks Ken.

[Basa Mallika Gogulamudi]

Challenge Question 16 : Squaring fractions.

 

(3 5/6)^2 = D(3) D(3 5/6) D(5/6)

= 9  (2 x3x 5/6 ) 25/36

= 9 (30/6) 25 /36

= 9 + 5 25/36

= 14 25/36

 

Conventional way :

(3 5/6 ) ^2 =  ( 23 / 6)^2

=  529 /36

= 14 25/36

 

Regards.

[Basa Mallika Gogulamudi]

Hi Ken,

I have reworked the sums using your suggestions. This looks a lot easier for me now.

Thanks a ton for all the patience. 🙂

Attached the reworked sums.

Regards.

Attachments:

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[Basa Mallika Gogulamudi]

Hi Ken,

Thanks for the explanation. This is how I solved it (attached).  Please let me know if any corrections are needed.

Triples subtraction is introduced in later videos I guess (Lesson 13 in the book).

Regards.

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[Basa Mallika Gogulamudi]

Hi Ken,

This is regarding Triples. I solved all the problems from chapter 9 (TM – IL) except c and d in Practice E. (picture attached)

I am not sure whether I didn’t understand the sums correctly or it was a printing error.

Please help me out.

Regards,

Mallika

Attachments:

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[Basa Mallika Gogulamudi]

Challenge Question 14:

Using bar numbers we can eliminate carry forward and simplify calculations.

Using bar numbers:

9 ) 3 2 (3)  2

___________
3 5 2 r 4

Without using bar numbers:

9 ) 3 1 7 2

_________

3 4 1 r 13

1

_________

352 r 4

Regards.

 

 

 

 

 

[Basa Mallika Gogulamudi]

Challenge Question 12:

Converting  Fahrenheit to Centigrade ( Subtract 32, add a tenth and halve) to give approximate conversion.

For exact conversion we have to use add a ninth instead of tenth.

<b>Subtract 32, add a <i><u>ninth</u></i> and halve to get exact conversion.</b>

Regards.

[Basa Mallika Gogulamudi]

Challenge Question 11:

47 x 67 = 3149

We can solve this problem by using first by first and last by last sutra.

We multiply digits in tens place that add up to 10 (4×6 ) and add units place number (7) to the final answer   24+7 = 31

we simply multiply digits in units place to get the second part of the answer. 7×7 = 49

47 x 67 = 3149

 

94 x 67 can be solved using proportionately sutra.

94 = 47×2

 

67 x 47 = 3149 and we double the answer to solve 94 x 67 = 6298

<b>32 x 36 can be solved using proportionately sutra again.</b>

We double 36 to get 72.

32×72 = 2304 and we halve the result to get final answer 1152.

Regards.

 

[Basa Mallika Gogulamudi]

Hi Ken, I have a doubt regarding quiz. Will I be able to do week 4 quiz next week or should we complete it by today?

Regards.

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