Week 7 Video Lessons

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    • #28847
      Pasyanthi
      Keymaster

      Please use this thread to post your questions/Comments/impressions/Learnings etc on topics covered in week 7 video lessons

    • #32052

      Hi,

      I want to share this with the class.

      This is regarding coordinate geometry, perpendicular lines.

      We should interchange the coefficients and change one sign to find the equation of the line through a given point and perpendicular to the line. In that case we will have two possible answers (one positive and one negative).

      For example: (-3, 4) , 5x -2y =3

      Scenario 1 : 2x+5y = 14

      Scenario 2 : -2x-5y = -14

      Both scenarios plot the same line(same equation) extending over different quadrants.

      Regards.

    • #32562
      Savita P Kulkarni
      Participant

      Hi Mallika,

      You are right that there are 2 possibilities because we can change the sign of either of the x or y coefficients. Even if we are getting two possible answers, the equation of the line remains the same because the line is extended into the two quadrants.

      2x+5y+14

      5y= -2x+14

      y=- 2/5 x+14/5

      and -2x-5y=-14

      5y=-2x+14

      y=-2/5 x+14/5

      Thank you for pointing that out,

       

      • #32571
        KennethWilliams
        Keymaster

        Hi Savita,

        There is only one line and one equation.

        2x+5y=14 is exactly equivalent to -2x-5y=-14 mathematically.

        One equation – one line.

    • #32563
      Savita P Kulkarni
      Participant

      Hi mr. Ken,

      Mr. James, the deputy head of math dept. in James school of London has come up with the method of finding the equation of a line passing through a given point and either parallel or perpendicular to a given line. What does it say in Shree Bharati Krishnaji’s book?

      Thanks,

      • #32573
        KennethWilliams
        Keymaster

        Hi Savita,

        Sri Bharati Krishna’s book does not mention this topic.

        Mathematics is a vast subject and the book cannot cover everything. James Glover’s discovery directly relates to the Vedic Sutras and is simple and easy to understand. Hence we can include it as Vedic Maths.

    • #32564
      Savita P Kulkarni
      Participant

      Hi Mr. Ken,

      In the Vedic method for finding the equations of lines why and how do we start with the standard format of

      y=mx+c?

      Thanks,

       

      • #32578
        KennethWilliams
        Keymaster

        Hi Savita,

        y=mx+c is a standard form for straight lines. That is because by substituting specific values for m and c the equation always plots out to a straight, and all lines are inlcuded.
        The nice thing about y=mx+c is that it turns out that m is the gradient (slope) of the line, and c is the intercept on the y-axis.

        Another standard form for a straight line is ax+by=c, so y=mx+c is not the only one.

    • #32660
      Fabio Zanatta
      Participant

      Hello,

      for straight line the equation is y=mx+q or (y-yp)=m(x-xp).

      For perpendicular line the equation is (y-yp)=-(1/m)(x-xp).

      The angular coefficient is m in the first case and -1/m in the second case. This is the reason (video lesson 28) for the calculus to find the line who pass for P(3,1) and perpendicular to 2x+3y=5. Into this example we substitute (3,1) in 3x-2y and not in 2x+3y.

      This is correct?

      Thanks

    • #33024
      Amara Deepthi
      Participant

      Ken,

      The general square rooting method and finding the recurring decimals is so enlightening. Even the calculator was not showing the complete pattern for recurring decimals. Felt so nice to see that. Thank you so much Ken for sharing these methods with us.

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