February 26, 2021 at 12:00 am #28847PasyanthiKeymaster
Please use this thread to post your questions/Comments/impressions/Learnings etc on topics covered in week 7 video lessons
February 26, 2021 at 8:29 pm #32052Basa Mallika GogulamudiParticipant
I want to share this with the class.
This is regarding coordinate geometry, perpendicular lines.
We should interchange the coefficients and change one sign to find the equation of the line through a given point and perpendicular to the line. In that case we will have two possible answers (one positive and one negative).
For example: (-3, 4) , 5x -2y =3
Scenario 1 : 2x+5y = 14
Scenario 2 : -2x-5y = -14
Both scenarios plot the same line(same equation) extending over different quadrants.
February 28, 2021 at 5:17 pm #32562
You are right that there are 2 possibilities because we can change the sign of either of the x or y coefficients. Even if we are getting two possible answers, the equation of the line remains the same because the line is extended into the two quadrants.
y=- 2/5 x+14/5
Thank you for pointing that out,
February 28, 2021 at 6:36 pm #32571
There is only one line and one equation.
2x+5y=14 is exactly equivalent to -2x-5y=-14 mathematically.
One equation – one line.
February 28, 2021 at 5:22 pm #32563
Hi mr. Ken,
Mr. James, the deputy head of math dept. in James school of London has come up with the method of finding the equation of a line passing through a given point and either parallel or perpendicular to a given line. What does it say in Shree Bharati Krishnaji’s book?
February 28, 2021 at 6:39 pm #32573
Sri Bharati Krishna’s book does not mention this topic.
Mathematics is a vast subject and the book cannot cover everything. James Glover’s discovery directly relates to the Vedic Sutras and is simple and easy to understand. Hence we can include it as Vedic Maths.
February 28, 2021 at 5:30 pm #32564
Hi Mr. Ken,
In the Vedic method for finding the equations of lines why and how do we start with the standard format of
February 28, 2021 at 6:43 pm #32578
y=mx+c is a standard form for straight lines. That is because by substituting specific values for m and c the equation always plots out to a straight, and all lines are inlcuded.
The nice thing about y=mx+c is that it turns out that m is the gradient (slope) of the line, and c is the intercept on the y-axis.
Another standard form for a straight line is ax+by=c, so y=mx+c is not the only one.
February 28, 2021 at 8:27 pm #32660Fabio ZanattaParticipant
for straight line the equation is y=mx+q or (y-yp)=m(x-xp).
For perpendicular line the equation is (y-yp)=-(1/m)(x-xp).
The angular coefficient is m in the first case and -1/m in the second case. This is the reason (video lesson 28) for the calculus to find the line who pass for P(3,1) and perpendicular to 2x+3y=5. Into this example we substitute (3,1) in 3x-2y and not in 2x+3y.
This is correct?
February 28, 2021 at 9:51 pm #32661
Yes that is correct Fabio.
March 7, 2021 at 12:21 am #33024Amara DeepthiParticipant
The general square rooting method and finding the recurring decimals is so enlightening. Even the calculator was not showing the complete pattern for recurring decimals. Felt so nice to see that. Thank you so much Ken for sharing these methods with us.
- You must be logged in to reply to this topic.