[KennethWilliams]

Hi Shikha,

15th Feb is the final date.

[KennethWilliams]

Hi Seth,

You should come to the page “Assignment – 1 – Write a Lesson Plan” before going into week 4.

At the top of that page is a link, in red, where you can get the template.

[KennethWilliams]

Hi Seth,

I hope you are not thinking that in VM we only calculate from left to right, because that is not so. Both are useful and the Vedic mathematician chooses the best method at any time: right to left or left to right.

Certainly right to left is better sometimes, and educationally it makes sense to learn right to left first of all because we start with learning about units before tens and so on.

We do focus more on the left to right direction on this course, but that is because people are very familiar with right to left methods already. And as you will see there are many advantages of working that way.

[KennethWilliams]

Hi Mallika,

I meant 1 1/3 x 2 1/4, multiplication, not addition.

[KennethWilliams]

Hi Mallika,

Suppose you want 1 1/3 + 2 1/4 (1 and a third + 2 and a quarter):

1           1/3
2          1/4

You multiply vertically on the left, then the two crosswise multiplications, then vertically on the right.

Adding these four products gives the answer.

 

[KennethWilliams]

Challenge Question 8 – Missing Digits

Two 2-figure numbers are multiplied to get a 4-figure number.
But some of the digits get smudged, so we can only see:
21 x ?? = ??12.
Can you find the missing digits?

[KennethWilliams]

Thanks for these answers to Questions 5 and 6 – excellent.

Challenge Question 7

Can bar numbers be useful in fractions work?
For example to find 4 9/11 + 3 7/8 (that’s four and nine elevenths plus three and seven eighths)?
Note: the numbers are close to 5 and 4 respectively.
[Please wait 24 hours before answering]

[KennethWilliams]

Hi Savita,

The way to tackle this question is to first use the Last By Last Sutra. By looking at the last digits of the three numbers you can see that b must be 7, it cannot be any other number.

Then the digit sums will give the value of a.

Multiplication of 3-digit by 2-digit numbers is dealt with in lesson 21.

[KennethWilliams]

Thanks for all these great and creative answers.
Be sure to read other people’s answers.

Please post your answer even if someone else has already posted it.

[KennethWilliams]

Challenge Question 6 – multiplication by 111

We know how to easily multiply by 11.

Can this be extended to multiplication by 111?

For example 234 x 111.

[KennethWilliams]

Challenge Question 5 – Two Smudged Digits

The product of two numbers is seen but two of the digits are smudged. So you can only see:

3 a b   x   6 1   =   1 9 9 4 7

where a and b are the smudged digits.

Can you find the smudged digits (please explain your answer)?

[KennethWilliams]

Hi Savita,

The Manuals are available here:
https://www.vedicmaths.org/shop/books

Manual 1 can be downloaded for free:
https://www.vedicmaths.org/resources/books/free

The template for the assignment will soon be available.

[KennethWilliams]

Thanks Shikha. Correct except no 5 is 76971.

[KennethWilliams]

That’s right Fabio.

If the denominators have a common factor you divide them both by that factor.

You don’t have to do it but it makes the calculation easier.

[KennethWilliams]

Yes, you’ve got 3 of them now because only 4-figure answers were requested.

2 more to go.

[Author]

Posts