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As 40 is our base number, it has single 0 hence we will have single digit in the right half of the answer.
Hi Satya,
After getting 176/(12), we should subtract (1) from 176 as it is a carry and that will give us 175/(2). Now we have to remove (2) and the answer will be 1748.
Hope that helps!!
Regards.
Thanks Ken.
1 1/3
2 1/4
1*2 + 2*1/3 + 1*1/4 + 1/3 * 1/4
2+3 7/12+ 1/12
5 8/12 is the answer I am getting.
but if I convert same fractions into improper fractions and do multiplication
4/3* 9/4 = 43/12 = 3 7/12.
somewhere I am going wrong Ken.
Regards.
Challenge Question 7:
4 9/11 + 3 7/8
we add wholes and convert 9,8,7 to bar numbers.
7 1(1) /11 + 1(3)/1(2)
We multiply crosswise and add to get numerator.
7 1(3)2 + 1(23) / 1(12)
We multiply denominators to get denominators
7 2(51) / 1(12)
7 149/88
8 61/88
We can use bar numbers in fractions. But I found it little complicated to use them. Looking forward to see different approaches
Regards,
Mallika
Hi Ken,
I have watched lesson 13. I didn’t understand how to multiply mixed fractions without converting them to improper fractions. I tried to apply vertical crosswise, but somehow I didn’t get it. Can you pls help me.
thanks,
Mallika
Hi Sativa,
77(03)1 –
7 in ten thousands place is written as it is.
Second step, subtract 03 from 700. 700-03=697
1 in units place is written as it is.
76971
Thanks.
🙂 Sorry Ken. I got carried away by permutations and combinations. 🙂
I am glad I signed up for this course – this course is helping challenge my thought process. 🙂
Here are those 5:
202(1)
3(99)9
3(981)
1(8)02(1)
1(799)9
Are these same 5 you had in mind? Or are there other combinations?
I validated these with the digit sum. Is there a way to know how many combinations possible by looking at the number?
Regards.
Challenge Question 4
In how many ways can the number 2019 be represented as a 4-figure number, what are those representations?
Scenario 1 : When repetition of digits are allowed, we can write 2019 4-figure number in 3*4*4*4 = 192 ways.
Thousand’s place will have only 3 possible ways (2,9,1) because, if we use 0 it will become 3-figure number.
In Hundred’s, ten’s and unit’s place we can use any digits as repetition is allowed.
T h(9,1,2) H(0,1,2,9) T (0,1,2,9) U(0,1,2,9)
Example : 9999,1209, 2221, 1192 etc
Scenario 2: when repetition is not allowed, we can write 2019 4-figure number in 3*3*2*1 = 18 different ways.
Thousand’s place value will have 3 possible options – 2,1,9 Example: we take 9
Hundred’s place value will have 3 possible options – any of three numbers except the one used in thousand’s place. Example: we can take any one digit other than 9 so let us take 1;91
Ten’s place value will have 2 possible options – any one of the two numbers that are not used in thousand’s and hundred’s place. Example : we can take 2; 912
Unit’s place value will have 1 possible option – use digit that not used in above three. Example 0. ; 9120
Th (9,1,2) H(one of any 3 digits other than the one used in Th’s place) T(one of two digits other than digits used in Th’s and H’s place) U(Whatever digits is left).
2019 , 2091, 2901, 2910, 2109 ,2190
9012, 9021, 9102, 9120, 9210, 9201
1029, 1092 , 1902, 1920, 1209, 1290
Thanks.
Hi,
This is regarding fractions.
We can add or subtract mixed fractions without converting them into improper fractions.
But for multiplication and division, we have to convert mixed fractions into improper fractions before doing the operation.
Is there any easy method or am I missing something?
Thanks, Mallika.
Hi Ken,
It has generated html code for my post 🙁 I have tried to edit it but no luck.
My original post says if we subtract positive number from it’s bar number the answer is always zero and thought of using this for checking mechanism. But digit sum is easy way to do it. Thank You Ken.
Thanks, Mallika
