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#30554
KennethWilliams
Keymaster

From the 15 you subtract 3*1 to get 12. You can’t put down 12 because you know the next number will be 9 at most.

So you put down 9, and the other 3 (from that 12) is prefixed to the next digit to give 34.

Now taking 3*9 from 34 gives 7. But this is too big because at the next step you will be taking 21 from 6. So the 7 must be reduced, and you find it needs to go down to a 5 because then you will have 26 – 3*5 which is the remainder 11.

I hope this makes sense – full makes for determination 🙂

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