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#29861
Anupama Cherukuri
Participant

Challenge Question 5 : applying vertical and cross wise sutra:

3  a  b  X 61 – here 0 is in hundred place – so 061

The last digit in answer 19947 is 7 so b must be 7  – 3 a 7 so far

3x 0      (3×6)+(aX0)         (3X1) + (7X0)+(aX6)       (aX1)+(7X6)         (1X7)

0                 18                         3 +0+6a                                42+a                    7

18                        3+(6X 2)+ 4 (carry over)  to get 19 here ‘a’ must be 2           42 + 2             7

18                                15                              44                 7

= 19947

so the answer is 327

 

 

 

 

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