Certificate in Calculus Test 03 (CCT03)

Question 1 of 6

2 point(s)

The gradient of the tangent to y = x² at x = -8 is:

Question 2 of 6

3 point(s)

The gradient of the tangent of the curve y = 2x² – 4x + 1 at x = 3 is:

Question 3 of 6

2 point(s)

Given y = 3x² + 4x + 5, dy/dx =

Question 4 of 6

3 point(s)

Given P = 2q² + 3q + 1, dP/dq =

Question 5 of 6

4 point(s)

The x-coordinate of the point on y = 3x² + 4x + 5 where the gradient is 16 is:

Question 6 of 6

3 point(s)

Given y = 7 – 3x + 3x² then dy/dx =

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