Reply To: Challenge Questions – 2

Home Forums VMTTC Online Discussion Forum Challenge Questions – 2 Reply To: Challenge Questions – 2

#32839

Hi,

123 x ??? = 321??

if I pair 1st two numbers

12 3 x ?? ? = 321 ??

if I divide 321 with 12 I get 26 remainder 9

12 3 x 26 ? = 312 and 9 is a carry from crosswise multiplication.

26 x 3 = 78 +12 x 1= 90 so  last digit should be 1 in the multiplier.

123 x 261 = 32103

 

Regards.

error:
Scroll to Top
Visit Us On FacebookVisit Us On Youtube