I have a question on Samuccaya Sutra.
The lesson 17 consider the equation 1/(x-3) + 1/(x-5) = 1/(x-2)+ 1/(x-6)
If I understand correctly, the Sutra say that (x-3)+(x-5)=2x-8 from the left side of the equation and (x-2)+(x-6)=2x-8 from the right side of the equation. Because we have 2x-8 (results are equals) from both sides of the equation, we calculate x=4.
This is correct? Thanks