Reply To: Challenge Questions

[Preeti Pathak]

Hello,

Answer of challenge question 5

3 ab * 61=19947

First of all, see  the digit in the units place of the answer.It is 7.

Applying “Last by Last”sutra,we get b=7.

Now,

3 a*7* 61=19947

21a*61= 19947

Applying digit sums,

digit sum of 19947=3(casting out 9’s)

Numbers                            Digit sums

21a                                        3+a

61 *                                        7 *

——–                                ———

19947                                   3

In the digit sums column,

(3+a) * 7 = 3

21 * 7a =3

again, applying digit sums,

3 * 7a=3

for this to be true, 7a=9,implies a=2

so the smudged digits are b=7 and a=2

327 * 61=19947

Thanks