Reply To: Week 2 Video Lessons

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Fabio Zanatta

Hello everyone,

I have a question on Russian multiplication.

I understand the method as follow:

I consider the multiplication 8×6=48. The 8 (4th finger on the left hand) have 3 fingers at his left. The 6 (2nd finger on the right hand) have only 1 finger at his right. I sum 3+1=4 and I have the first result digit.

Now, I multiply 4×2=8 because the 8 is the 4th number and 6 is the 2nd and I obtain the second result digit.

This is correct?

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