I have a question on Russian multiplication.
I understand the method as follow:
I consider the multiplication 8×6=48. The 8 (4th finger on the left hand) have 3 fingers at his left. The 6 (2nd finger on the right hand) have only 1 finger at his right. I sum 3+1=4 and I have the first result digit.
Now, I multiply 4×2=8 because the 8 is the 4th number and 6 is the 2nd and I obtain the second result digit.
This is correct?